A-B = 3, ab = 2, the square of a + the square of B =?

A-B = 3, ab = 2, the square of a + the square of B =?

solution
a²+b²
=a²-2ab+b²+2ab
=(a-b)²+2ab
=3²+2×2
=9+4
=13

The square of a + the square of B = 3, A-B = 2, find the square of ab

a-b=2
Then the square of (a-b) = 4
Square of a-2ab + square of B = 4
Square of a + square of B = 3
3-2ab=4
ab=-1/2

A + B = - 3, ab = 2, a square + b square = (), (a-b) square = ()

a²+b²=（5）,(a-b)²=（1）
∵(a+b)=-3
∴(a+b)²=9
That is a & # 178; + 2Ab + B & # 178; = 9 ①
∵ab=2
∴2ab=4………… ②
① - 2
a²+b²=5
(a-b)²
=a²-2ab+b²
=(a²+2ab+b²)-4ab
=(a+b)²-4ab
=9-4×2
=9-8
=1