The difference factorization of the difference between the square of x plus 2 y and the square of x minus 3 y divided by Y minus x

The difference factorization of the difference between the square of x plus 2 y and the square of x minus 3 y divided by Y minus x

[（x+2y）^2-(x-3y)^2]/y -x
=(x+2y-x+3y)(x+2y+x-3y)/y -x
=5y（2x-y）/y -x
=10x-5y-x
=9x-5y

The square factorization of (the square of 2 multiplied by the square of x minus the square of 1)

The title is not easy to understand. It's better to write down the formula
Such as: (2 ^ 2 * (x ^ 2-1) ^ 2) ^ 2
Then = 2 ^ 4 * (x-1) ^ 4 * (x + 1) ^ 4

99 by 199 99 by 199 + 199

99×199
=(100-1)×199
=100×199-199
=19900-199
=19701
99×199+199
=199×(99+1)
=199×100
=19900

First simplify, then evaluate. (X-2) (x + 3) - x (X-2), where x = negative half

Original formula = (X-2) (x + 3-x)
=3(x-2)
When x = - 1 / 2 3 (X-2) = 3 (- 1 / 2-2) = - 15 / 2

1+1+2+2+3+3+4+4…… How much is 500 + 500? How to use the formula?

Because 1 + 2 + +500 = 5050, so 5050 * 2 = 10100