Find the value of (the second power of 5A - the second power of 3ab-2b), where the second power of a + the second power of B = 10, ab = 3

Find the value of (the second power of 5A - the second power of 3ab-2b), where the second power of a + the second power of B = 10, ab = 3

If the quadratic power of a-Ab = 9, the quadratic power of ab-b = 4, then the quadratic power of A-B = [], the quadratic power of a-2ab + B = []

∵a2-ab=9,ab-b2=4
∴a2- b2= (a2-ab)+ (ab-b2)= 9+4=13
∴a2-2ab+b2=(a2-ab)- (ab-b2)=9-4=5

Given a ^ + B ^ + 4b-a + 17 / 4 = 0, what is the value of a ^ + B ^?
Please clarify the process,

It is known that a & sup2; + B & sup2; + 4b-a + 17 / 4 = 0
Then: A & sup2; - A + 1 / 4 + B & sup2; + 4B + 4 = 0
(a-1/2)²+(b+2)²=0
a=1/2,b=-2
a²+b²=1/4+4=17/4

If x is greater than y and greater than 0, compare (square of x plus square of Y) (x minus y) and (square of x minus square of Y) (x plus y)

0＜y＜x【(x^2+y^2)(x-y)】-【(x^2-y^2)(x+y)】=【(x^2+y^2)(x-y)】-【(x-y)(x+y)^2】=(x-y)【(x^2+y^2-(x+y)^2】=(x-y)(-2xy)=-2xy(x-y)＜0【(x^2+y^2)(x-y)】＜【(x^2-y^2)(x+y)】

Given the sixth power of W + the third power of W = - 1, evaluate the square of 1-w-w + the third power of W - the fourth power of W - the fifth power of W
+The sixth power of W - the seventh power of W - the eighth power of W

The sixth power of W + the third power of W = - 11 - the square of W - the third power of W - the fourth power of W - the fifth power of W + the sixth power of W - the seventh power of W - the eighth power of W = 1 - the square of W - the third power of W + the fourth power of W - the seventh power of W - the fifth power of W - the eighth power of W = 1 - the square of W + (the third power of W + the sixth power of W) - w (w

If we know that a + 1 / a = 3, the fourth power of a evaluation / A + the square of a + 1 will be substituted into the evaluation

Can you make the title clear? Is it a + 1 / a = 3
Find the value of a ^ 2 / (a ^ 4 + A ^ 2 + 1), and replace a with a?

From 1 = square. 2 + 3 + 4 = 3 square. 3 + 4 + 5 + 6 + 7 = 5 square, we can get the general rule as (expressed by numerical expression)

[n - (n-1) / 2] +... + [n-1] + N + [n + 1] +... + [n + (n-1) / 2] = n square

1,-2,3,-4,5,-6,7,-8,… The law is expressed by formula
For example: 2,4,6,8,10,12
It is expressed by formula 2n

n*(-1)^(n+1)

First simplify, then evaluate: X-Y divided into x + y △ (x + y) &# 178;, where x = 4, y = - 2

=(x+y)/(x-y)×1/(x+y)²
=1/(x+y)(x-y)
=1/(x²-y²)
When x = 4, y = - 2
Original formula = 1 / (16-4) = 1 / 12

First simplify, then evaluate: (A-4) a - (a + 6) (A-2), where a = -12

The original formula = a2-4a - (A2 + 4a-12), = a2-4a-a2-4a + 12 = - 8A + 12. When a = - 12, the original formula = - 8 × (- 12) + 12, = 4 + 12, = 16