The equation of a line passing through the origin and tangent to the curve y = x3-3x2 + 2x

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• 1. F (x) = x & # 179; - 3x & # 178; + 3ax-3a + 3 (1) find the tangent equation of the curve y = f (x) at (1, f (1)) (2) x belongs to [0,2], Find the maximum value of | f (x) |
• 2. Find the normal equation of curve y = arctan2x at point (0,0)
• 3. Finding the normal equation The normal equation of surface z = 2x square + y square at point (1,1,3) is
• 4. Make all lines at a point a on the curve y = x * 2 (x is greater than or equal to 0) so that the area enclosed by the curve and X axis is 1 / 12. Try to find the tangent point a and tangent square What's the process? I'll understand. Help
• 5. Make all lines at a point a on the curve y = X2 (x ≥ 0) so that the area between them and the figure surrounded by the curve and x-axis is 112. Try to find the coordinates of tangent point a and the tangent equation passing through tangent point a
• 6. Find the special solution of the differential equation y '= e ^ (x + y) satisfying the initial condition y (0) = 0
• 7. Find the general solution of the differential equation y '' - 2Y + 2Y = e ^ xsinx,
• 8. General solution of differential equation y "- y = e ^ x
• 9. Calculating the general solution of differential equation y '+ y-e ^ (- x) = 0
• 10. General and special solutions of differential equations XY '= 2Y why is y = 5x ^ 2 a special solution of the differential equation? Isn't the definition of a special solution a solution without any constant? Why isn't 5 an arbitrary constant?
• 11. Given that any value of even function f (x) on R has derivative, and f '(1) = 1, f (x + 2 = f (X-2), then the slope of tangent of curve y = f (x) at x = - 5 is I use the substitution method to calculate t = 4, f (- 5 + 4) = f (- 1), and then even function f '(- 1) = f' (1) = 1. If I do this, I can calculate k = 1, but the answer is - 1 What's wrong with me in this way or the answer is wrong
• 12. If the tangent of the curve y = X3 + X-2 at point P0 is parallel to the straight line y = 4x, then the coordinate of point P0 is () A. (0, 1) B. (1, 0) C. (- 1, - 4) or (1, 0) d. (- 1, - 4)
• 13. The special solution of the differential equation y ′ SiNx = ylny satisfying the initial condition (when x = π / 2, y = e) is? It is better to write out the steps to solve the problem
• 14. Find the solution of the differential equation of this separable variable: y '= 10 ^ (x + y)
• 15. Find the tangent equation of the curve xy = 1 at x = 2, and find the area of the triangle formed by the tangent and the two axes "Find the tangent equation of the curve xy = 1 at x = 2, and find the area of the triangle formed by the tangent and the two coordinate axes."
• 16. Let a curve have y = x + 1 / X-1, and the tangent at point (3,2) is perpendicular to the straight line ax + y + 1 = 0, then a is equal to? y=(x+1)/(x-1)=1+[2/(x-1)] y'=-2/(x-1)² When x = 3, y '= - 2 / (3-1) & # 178; = - 1 / 2 The tangent of the point is perpendicular to the line ax + y + 1 = 0 That is, their slope product is - 1 -1/2×(-a)=-1 The solution is a = - 2, -1/2×(-a)=-1 Why - A is not clear
• 17. If the tangent of the square of the curve y = ax - ax + 1 at the point (1,0) is perpendicular to the straight line 2x + y + 1 = 0, then a is equal to? Wrong, at (0,1)
• 18. Let the tangent of the curve y = AX2 at point (1, a) be parallel to the straight line 2x-y-6 = 0, then the value of a is______ ．
• 19. Find the chord length of the line y = 2x-1 cut by the ellipse x ^ 2 / 4 + y ^ 2 / 9 = 1
• 20. 1. X & # 178; + xy-2y & # 178; 2. M & # 178; + 5mn-50n & # 178; 3. (x + 1) &# 178; - x (x + 2) factorization