Find the tangent equation of the curve xy = 1 at x = 2, and find the area of the triangle formed by the tangent and the two axes "Find the tangent equation of the curve xy = 1 at x = 2, and find the area of the triangle formed by the tangent and the two coordinate axes."

Because the curve xy = 1, so y = 1 / x, derivative y '= - 1 / x ^ 2, substituting x = 2 to get y' = - 1 / 4, let the straight line be y = KX + B, k = - 1 / 4, substituting x = 2 into xy = 1 to get the point (2,1 / 2), then substituting x = 2 into the straight line to get b = 1, so the straight line is y = - 1 / 4x + 1, intersecting with the X axis (4,0), intersecting with the Y axis (0,1), so the triangle area is 4x1x1 / 2 = 2

Tangent equation of ordinate y = 0 on curve e ^ XY + 2x + y = 3

Y = 0, substituting, we get x = 1, the curve goes through (1,0)
On the derivation of X:
e^xy(xy'+y)+2+y'=0
Substituting (1,0) has y '= - 1
So the tangent is y-0 = - 1 (x-1)
We get x + y = 1

Finding the special solution of the differential equation with separable variables satisfying the given initial conditions
Y '= 2x-y power of E; X = 0, y = 0

∵y'=e^(2x-y) ==>e^ydy=e^(2x)dx
==>E ^ y = e ^ (2x) / 2 + C (C is an integral constant)
And when x = 0, y = 0
∴ 1=1/2+C ==>C=1/2
So the special solution e ^ y = [e ^ (2x) + 1] / 2 satisfying the given initial condition

Let the random variables (x, y) obey the uniform distribution in the triangle region D with the vertices of points (0,1), (1,0) (1,1), and find D (x)
If you know how to add me
1: There are three workshops in a factory, and the products produced in each workshop account for 50% 20% 30% of the total number. According to the past experience, the probability of product occurrence in each workshop is 5% 4% 3%. The probability of random sampling of the same product is unqualified.
Finding matrix A = - 4 - 100
Eigenvalues and eigenvectors of 130? right off
3 6 1

The probability density is the reciprocal of the area: F (x, x, y) = 1 / S = 2F (x) is the reciprocal of the area: F (x, y) = 1 / S = 2F (x) = ∫ (1-x, 1) f (x, y) f (x, y) is the reciprocal of the area: F (x (x, x, y) is the reciprocal of the area: F (x, x, y) = 1 / S = 2F (f (x, x, y) = 1 / S = 2F (f (x (x, x, y) as the reciprocal of the area: F (x (x, x, y, y) is the reciprocal of the probability density is the reciprocal of the area: F (x (x (x, x, x, y, y, y) is the probability density is the reciprocal of the inverse of the probability distribution of the probability distribution of the probability distribution: F (probability distribution: the probability density is the inverse of the inverse of the area: F (Probability: F (Probability: F (f (f/ 2D (x) = ex & #

1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2?

All lines minus line 2
D =
-1 0 0 ...0
2 2 2 ...2
0 0 1 ...0
...
0 0 0 ...n-2
c1-c2
-1 0 0 ...0
0 2 2 ...2
0 0 1 ...0
...
0 0 0 ...n-2
D = -2 (n-2)!

Probability problem: if the two-dimensional random variable (x, y) in the plane region D = {(x, y): - 1

1/2

Find the tangent equation of the curve xy = 1 at x = 2, and find the area of the triangle formed by the tangent and the two axes "Find the tangent equation of the curve xy = 1 at x = 2, and find the area of the triangle formed by the tangent and the two coordinate axes."