Given the function f (x) = 3xx ≤ 1 − XX > 1, if f (x) = 2, then x=______ ．

Given the function f (x) = 3xx ≤ 1 − XX > 1, if f (x) = 2, then x=______ ．

From X ≤ 13X = 2 {x = log32, X ＞ 1 − x = 2 {x = − 2, there is no solution, so the answer: log32

If f (x) = x (AX + 1) is an odd function on R, then what is a equal to?

f(-x)
= (-x)(-ax + 1)
= x(ax - 1)
-f(x)
= -x(ax+1)
Because f (x) is an odd function
So f (- x) = - f (x)
So x (AX - 1) = - x (AX + 1)
So ax - 1 = - ax - 1
So a = 0

A ∈ [- 1.1], then the probability of F (x) = ax ^ 2 + X being an increasing function on [- 1.1] is equal to. On line, etc. velocity
The best mapping. To solve the problem ideas

F '(x) = 2aX + 1, because f (x) = ax ^ 2 + X is an increasing function on [- 1.1], so f' (x) = 2aX + 1 > 0 is constant on [- 1,1],
① When a ≥ 0, the minimum value of F '(x) = f' (- 1) = - 2A + 1 ≥ 0, a ≤ 1 / 2, so 0 ≤ a ≤ 1 / 2;
② When a