One X of E, X tends to 0 - why is the limit 0? | Math enthusiast | Mathematical art

One X of E, X tends to 0 - why is the limit 0?

X tends to zero-
That is, 1 / X tends to - ∞
So e ^ (1 / x) tends to 0

Why is the limit of 2 minus 1 / x plus one square of x 2 when x tends to be ∞

1 / ∞ = 0, so eventually 2 + 0 + 0 = 2

㏑ (1 + e Λ x) / E Λ x when x → infinity

The numerator and denominator of im (1 + e ^ x) / e ^ X are divided by e ^ x at the same time
=lim(1/e^x+1)
=0+1
=1
When x →∞, e ^ x →∞, 1 / e ^ x → 0

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