If n is a positive integer and X2N = 5, then (2x3n) 2 △ (4x2n)=______ ．

If n is a positive integer and X2N = 5, then (2x3n) 2 △ (4x2n)=______ ．

∵ n is a positive integer, and X2N = 5, ∵ (2x3n) 2 ^ (4x2n) = 4x6n ^ (4x2n) = (4 ^ 4) x6n-2n = x4n = (X2N) 2 = 52 = 25

If M and N are opposite numbers, X is the smallest nonnegative number and Y is the smallest positive integer, then (M + n) y + y-x=______ ．

According to the meaning of the question: M + n = 0, x = 0, y = 1, then the original formula = 1

If a and B are opposite to each other, C is the smallest non negative number, D is the smallest positive integer, and X and y are reciprocal to each other, then the value of the algebraic formula (a + b) · D + d-c-xy is______ ．

When a + B = 0, C = 0, and D is the smallest positive integer, d = 1. X, y is reciprocal, xy = 1. When a + B = 0, C = 0, d = 1, xy = 1, (a + b) · D + d-c-xy = 0 + 1-0-1 = 0, the answer is: 0

It is known that x is a negative number with absolute value equal to 2, y is the largest negative integer, Z is the opposite number and equal to itself, so we can find the value of XY + Z

X is a negative number with an absolute value of 2
x=-2
Y is the largest negative integer
y=-1
Z is the opposite number equal to itself
z=0
z xy+z＝(-2)*(-1)+0=2

In the system of equations x + y = m, 2x-y = 6, it is known that XY is less than 0, and X and y are integers

x=2+m/3; y=2m/3-2
∵ XY less than 0 (6 + m) × (2m-6) ＜ 0
-6＜m＜3
And ∵ X and y are integers
Therefore, M is - 3,0

On the system of equations X-Y = m and 2x-y = m + 3 of XY, where the solution is positive and M is a negative integer, can we find the value of M?

We can get x = 3 because m is less than 0 and 3-y is greater than 0, M + 3 is greater than 0, so m is greater than - 3, so m = - 1 or - 2

1 / 14 = 1 / x + 1 / y + 1 / Z, XYZ is a different natural number. What is XYZ?

There are countless possibilities for this. Let's give it a possible solution
1/14=1/28+1/42+1/84.

A and B are two different numbers selected from the first 50 natural numbers. Find the maximum of A-B / A + B~

When B = 0, the original formula is 1
When B ≠ 0, the original formula is as follows:
a-b/a+b
=1-b/(a+b)
=1-1/(a/b+1)

Let X and y be two different numbers (x > y) selected from the first 100 natural numbers, and find the maximum value of X-Y / x + y

x-y/x+y=1-2y/x+y
=1+（-2/（x/y+1））
The larger X / y is, the smaller 2 / (x / y + 1) - 2 / (x / y + 1)
When x = 100, y = 1, X / y is the largest
x-y/x+y=99/101
But if the natural number includes 0, it cannot be divided if y = 0
x-y/x+y=1

Let X and y be two different numbers selected from the first 100 natural numbers, and find the maximum value of X-Y, x + y

X-Y\X+Y=1-2y/(x+y)
=1-2/（x/y+1）
Obviously, the larger X / y is, the smaller 2 / (x / y + 1) is
-The larger the 2Y / (x + y), the larger the X / y = 100 / 1, so the maximum is 99 / 101, and the x = 100y = 1
The above is when y is not 0, when y = 0, X-Y + X + y = 1 is the largest
It depends on whether 0 you learn is a natural number