tanx
First consider the case in the interval [- π / 2, π / 2]
If TaNx ≤ 0, then the value range of X is
(-0.5pi+n*pi,n*pi]
The value range of X with 1-tanx > 0
tanx
RELATED INFORMATIONS
- 1. Let a = {α | α = 2K π + π / 3, K ∈ Z} be the set of angles α Finding all angles of interval [- 4 π, 4 π] in set a
- 2. 2Sin (2 * π / 3 + θ) + 2 = 4, finally we get π / - 6 + 2K π. How can we get it! Given that the maximum value of the function y = sin (W + θ) + m is 4, the minimum value is 0, the minimum positive period is π / 2, and π / 3 is an axis of symmetry of its image, then the analytic expressions satisfying the conditions in the following expressions are
- 3. Among the following groups of numbers, only the two numbers with the common factor 1 are () A. 13 and 91b. 26 and 18C. 9 and 85
- 4. The number of common divisors of 9 and 24 is (). A.1 B.2 C.3 D.4 1 / 5 of a is equal to 30% of B, and the ratio of B to a is (). A.3:2 b.2:3 c.5:6 d.3:4 cut a square of 1 cubic centimeter into two rectangles, Surface area () A. increase 2 square centimeter B. increase 1 square centimeter C. no increase D. unable to decide 1 and 4 / 5 hours = () minutes () / 24 = 3 / 8-24: (). Calculation question. 3048 + 204 * 14 / 56 2 and 3 / 5 + 4.6 + 3 and 2 / 5 + 5.41 / (4 and 1 / 7-0.05 * 70) * 1 and 2 / 7 (0.36 * 7.4 + 0.36 * 2.6) * 3 and 4 / 50.56 * (2 and 5 / 12-1 and 19 / 60 + 2.375) / 0.514.7 * 98 + 14.7 * 3-14.7 Especially the calculation problem, thank you first,
- 5. What does the K in S = {β | β = α + K · 360 °, K ∈ Z} stand for
- 6. If {an} is an arithmetic sequence with tolerance 1, then {a2n-1 + 2a2n} is () A. Isochromatic sequence with tolerance 3 B. isochromatic sequence with tolerance 4 C. isochromatic sequence with tolerance 6 D. isochromatic sequence with tolerance 9
- 7. If we know the general term formula of arithmetic sequence {an} an = 3-2n, then its tolerance D is______ .
- 8. If {an} is an arithmetic sequence and D is a tolerance, then the new sequence formed by the sum of K items in this sequence will still be an arithmetic sequence, and the tolerance is DK ^ 2 Explain why the tolerance equals DK ^ 2
- 9. Given that the sum of the first n terms of the sequence {an} is Sn, and S (n + 1) = 4An + 2, A1 = 1, let CN = an / 2 ^ n, prove that the sequence {CN} is an arithmetic sequence
- 10. An is an arithmetic sequence, CN = an ^ 2-A (n + 1) ^ 2 (n ∈ n *) (1) Judge whether the sequence cn is an arithmetic sequence (2) If a1 + a3 + +A25 = 130, A2 + A4 +... + A26 = 143-13k (k is a constant), try to write the general term formula of the sequence CN
- 11. If | TaNx | / TaNx + 1 = 0, what is the value range of angle X
- 12. The value range of X when TaNx = 0
- 13. How to change the radian number to 2K π + α (0 ≤ α < 2 π) form? Read a lot of Baidu know, or do not understand For example: - 46 π / 3 Don't give me the solution directly, I want the explanation About the value of wealth... I will give more after reading the answer
- 14. Let 0 °≤ α≤ 2 π, then - 1485 ° be expressed as 2K π + α K in the form of Z
- 15. If β∈ [- 4 π, 0], and the terminal edge of β is the same as that of α in (1), then β is obtained
- 16. It is known that a is the first quadrant angle (360K < a < 360K + 90), so why is k divided into odd and even when finding out which quadrant angle A / 2 is And what quadrant angle is a / 3? K = 3k, k = 3K + 1, k = 3K + 2. Why
- 17. Let P: inequality x ^ 2 = 1 > A have two propositions, the solution set of P: inequality x ^ 2 = 1 > A is R; Q: 7-3a > 1 X ^ 2 = the square of X
- 18. The proposition "inequality m ^ 2 - M < x ^ 2 + X + 1 holds" is true. The range of real number m is obtained Methods only know that the right side of the inequality is always greater than 0 (x + 1 / 2) ^ 2 + 3 / 4 is greater than 0, and then it won't work. What should I do?
- 19. It is known that the solution set of the inequality kx-2 > 0 (K ≠ 0) about X is x < - 3, then the intersection of the line y = - KX + 2 and the X axis is X______ .
- 20. As shown in figure 1-5-1, the line y = KX + B (k)