Please judge the square of a - 2A + 3 and - 2A + 3

Please judge the square of a - 2A + 3 and - 2A + 3


The square of a - 2A + 3 - (- 2A + 3) = the square of a
If a = 0, then the square of a - 2A + 3 = - 2A + 3
When a is not equal to 0, the square of a is greater than 0
So the square of a - 2A + 3 > = - 2A + 3



Compare the square of a + the square of B with the value of 2 (2a-b) - 5


(a²+b²)-[2(2a-b)-5]
=a²-4a+4+b²+2b+1
=(a-2)²+(b+1)²≥0
So a & sup2; + B & sup2; ≥ 2 (2a-b) - 5



Given that a is a true fraction and a is not equal to 0, compare the square of a with the size of 2A


A is a true fraction, a is not equal to 0, so 0