The inclination angle of the tangent of the curve y = (1 / 5) x ^ 5 + 3x ^ 2 + 4x at x = 1 is

The inclination angle of the tangent of the curve y = (1 / 5) x ^ 5 + 3x ^ 2 + 4x at x = 1 is

y=(1/5)x^5+3x^2+4x
y'=x^4+6x+4
When x = 1, y '= 1 + 6 + 4 = 11
The inclination angle is arctan11

Given that the equation x + 2m = 4 (x + m) + 1 has a positive integer solution, the range of M is obtained
important

x+2m=4（x+m）+1
Namely
3x=-2m-1
x=(-2m-1)/3
Because the equation x + 2m = 4 (x + m) + 1 has a positive integer solution
That is to say
-2m-1 / 3 is an integer
have to
m=(-3n-1)/2
N is any positive integer

It is known that the equation (x-3 of x) - 2 = M-3 of X has a positive integer solution?
I've got 6-x = M. what should I do next

We have obtained: 6-x = M
x=6-m
The equation has a positive integer solution
x> 0 and X ≠ 3 and X is an integer
That is, 6-m > 0 and 6-m ≠ 3, and 6-m is an integer
Then M