It is known that the factorization result of the quadratic trinomial ax + bx-2 of X is (x + 1) (x-C), and the value of ABC is obtained

It is known that the factorization result of the quadratic trinomial ax + bx-2 of X is (x + 1) (x-C), and the value of ABC is obtained

∵ constant ax & # 178; + bx-2 = (x + 1) (x-C) = x & # 178; + (1-C) x-C
A = 1, B = 1-C, 2 = C
∴a=1,b=-1,c=2

It is known that the factorization result of the quadratic trinomial X & # 178; - ax + B is (x-1) (x + 2), and the values of a and B are obtained

（X-1）*(X+2)=X2+X-2=>
-a=1=> a=-1
b=-2

In the product of (x-mx + 1) (X-2), if the coefficient of the quadratic term of X is 0, then the value of M is ()

Let's multiply the formula to X & # 179; + (- 2-m) x & # 178; + (2mx + X-2), because the coefficient of quadratic term of X is 0, so - 2-m = 0, so m = - 2