Finding the maximum or minimum value of quadratic trinomial 2x ^ 2 + 8x

Finding the maximum or minimum value of quadratic trinomial 2x ^ 2 + 8x


2X^2+8X
=2X^2+8X+8-8
=2(X+2)^2-8
The square is greater than or equal to 0
2(X+2)^2>=0
2(X+2)^2-8>=-8
So minimum = - 8, no maximum



How to find the maximum or minimum value of quadratic function
How to find the maximum or minimum of quadratic function


The right half of the quadratic function is factorized and transformed into a complete square formula (with collocation method). Then we look at the positive and negative values of A. negative numbers have maximum values and positive numbers have minimum values. Then the last constant term is the maximum value



The minimum value of quadratic trinomial x2 + 5x + 7 is______ .


X2 + 5x + 7 = x2 + 5x + 254 + 34 = (x + 52) 2 + 34 ≥ 34, then the minimum value of quadratic trinomial x2 + 5x + 7 is 34