The solutions of the equations 4x + y = K + 1, x + 4Y = 3 satisfy X You seem to have miscalculated y, x = (K + 1-y) / 4

The solutions of the equations 4x + y = K + 1, x + 4Y = 3 satisfy X You seem to have miscalculated y, x = (K + 1-y) / 4

4X + y = K + 1
x=(k+1-y)/4
Substituting into formula 2, we get:
(k+1-y)/4+4y=3
The solution is y = (11-k) / 15
x=(k+1-y)/4

If the solutions of the equations 4x + y = 2K + 1, x + 2Y = 3 satisfy the condition - 2

4x+y=2k+1,x+2y=3
We can get y = 11 / 7 - 2K / 7 x = 4K / 7 - 1 / 7
So x + y = 10 / 7 + 2K / 7
-2

It is known that the solutions of the equations {4x + y + k = 1, x + 4Y = 7} are x, y and 0

Solve the equations
We can get x = (- 3-4k) / 15
y＝（27+k）／15
∴x-y＝（-3-4k－27-k）／15
＝-2-k／3
∵0＜k＜3
∴0＜k／3＜1
∴0＞-k/3＞-1
∴-2＞-2-k/3＞-3
-3＜x-y＜-2