What is the value of m when X-2 / 2 plus m equals 2-x / 1-x? (2/x-2)+m=1-x/2-x

What is the value of m when X-2 / 2 plus m equals 2-x / 1-x? (2/x-2)+m=1-x/2-x

(2+m)/(x-2)=(1-x)/(2-x)
It is necessary to have a solution for [(2 + m) + (1-x)] / (X-2) = 0
Then: if the denominator is not 0, the unique solution of the equation is that the numerator is 0
We get: 2 + m + 1-x = 0
X = 3 + m equation: denominator is not 0
That is X-2 ≠ 0
3+m-2≠0
When m ≠ 1

What is X-2 divided by (2 + x-2-x 4)

(X-2) x △ 2 + X - (2-x) 4]
=(X-2) of X △ [(x + 2) + (X-2) of 4]
=(X-2) of X ÷ (X-2) of [(x + 2) (X-2) + 4]
=(X-2) of X △ (X-2) of (X & # 178; - 4 + 4)
=X of (X-2) / (X-2) / (x-178);
=(X-2) Part X × X & # 178; part (X-2)
=1 / X

|X + 1 | - | X-1 | = 3 / 2
How to get the absolute value must be explained clearly,

This kind of problem should be discussed in different cases as follows: when x ≤ - 1, the original formula is equal to - (x + 1) + (x-1) ≥ 3 / 2; when 1 ＞ x ＞ - 1, the original formula is (x + 1) + (x-1) ≥ 3 / 2:; when x ≥ 1, the original formula is (x + 1) - (x-1) ≥ 3 / 2