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The mass of ice is 9kg, the density is 0.9 × 10 ~ (- 179); kg / M ~ (- 179). (1) calculate the volume of ice. (2) calculate the mass of water if 3DM ~ (- 179); of ice melts into water after heat absorption (1) Can we use scientific counting method to calculate the results of the test?
(1)V=m/ρ=9kg/0.9×103kg/m3=10^-2m3
(2) The ice melted by 2.7kg, that is, the ice reduced by V = 2.7kg/0.9 × 103kg / m3 = 0.310 ^ - 2m3
sure
Ice density = 0.9______ =_________ Three times of kg / M
ρ ice = 0.9g/cm & sup3; = 0.9 * 10 & sup3; kg / M & sup3;
The volume of water formed by ice with volume of 1 & sup3; (the density of water = 0.9 × 10 & sup3; kg / M & sup3;) is only a scientific problem
What is the volume of ice formed water with volume of 1 & sup3; (water density = 0.9 × 10 & sup3; kg / M & sup3;)
The known condition given in this question should be the density of ice: the density of ice = 0.9 × 10 & sup3; kg / M & sup3;
The density of water is generally considered to be 1.0 × 10 & sup3; kg / M & sup3
Mass = density * volume
So the volume of water = the volume of ice * the density of ice / the density of water = 0.9 m & sup3
That is, the volume of water is 0.9 cubic meters
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