(2a-b) x + 3a-4b is known

(2a-b) x + 3a-4b is known

(2a-b)x+3a-4b

-The second power of (- 3 / 5) - the third power of - 2 divided by the second power of (- 5),

-9/25-8/25=-17/25

How much is the second root of minus one? Thank you for your help
How to express negative two and negative three

Yes, in I1, it's plural

The power of 1 =, the power of 2 =

1 square = 1 * 1 = 1, 2 square = 2 * 2 = 4, 30 square = 30 * 30 = 900

A-B = 2, a-c = 1 / 2, then what is the cubic power of (B-C) - 3 (B-C) + 9 / 4?

A-B = 2, a-c = 1 / 2, then B-C = - 3 / 2, so the cubic power of (- 3 / 2) - 3 (- 3 / 2) + 9 / 4 = 27 / 8

How much is it from the 1st power of 2 to the 79th power of 2? How to calculate?

The sum formula Sn = A1 (1-Q ^ n) / (1-Q) where a1 = 2, the equal ratio coefficient q = 2 brings in SN = 2 * (2 ^ 79-1), that is, the 80th power of 2 minus 2 directly write 2 ^ 80-2 to calculate, then 1208925819614629174706174

What is the 21st power of 2

2097152

（-1）2015-22×（-12）3-（π-2）0．

The original formula = - 1-4 × (- 18) - 1 = - 1 + 12-1 = - 2 + 12 = - 32

How much is the power of 1997 divided by 7?

Because (7a + b) ^ C mod 7 = B ^ C mod 7
So 1997 ^ 2012 mod 7
=(7*285+2)^2012 mod 7
=2^2012 mod 7
=2^(3*670)*2^2 mod 7
=8^670*4 mod 7
=1^670 * 4 mod 7
=4 mod 7
The answer is 4

1 + 2 + 3 +... + 9, divided by 3

3,6,9: remainder 0
1: Yu 1
Second power: the remainder is 1
The fourth power is the remainder
To the power of 5: to the power of n of 5, to the power of 2,1,2,1,2,5, to the power of 2
7 power: the rest 1
To the power of 8: to the power of 2,1,2,1,2,1,2,1,8, to the power of 1
Add the remainder: 7
So the last one
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The remainder of any number divided by 3 can only be 2, 1, 0, and the n-th power of the number can be divided by 3. If the remainder is 2, the remainder is arranged from the first remainder according to the rule of 2, 1, 2, 1, 2, 1... For example, the 5th power of 5, starting from 5: remainder 2,25: remainder 1125: remainder 2
If the remainder is one, it will always be one