In △ ABC, it is known that ab = 102, a = 45 ° and the length of BC side is 202033 and 5 respectively, then the corresponding angle c is obtained

In △ ABC, it is known that ab = 102, a = 45 ° and the length of BC side is 202033 and 5 respectively, then the corresponding angle c is obtained

∵ C = 102, a = 45 °, when a = 20, from the sine theorem Asina = csinc, we can get: 2022 = 102sinc, ∵ sinc = 12, and a & gt; C, ∵ A & gt; C, ∵ C = 30 °; when a = 2033 & lt; 102 = C, we can get: sinc = 32, ∵ C = 60 ° or C = 120 °; when a = 5 & lt; 102 = C, we can get sinc = 2 & gt; In conclusion, when a = 20, C = 30 °, when a = 2033, C = 60 ° or C = 120 ° and when a = 5, C does not exist

I'm in a hurry! Sine and cosine theorem of mathematics in Senior Two,
1 in △ ABC, ∠ a = 60 °, a =, B = 4, then △ ABC (c) satisfies the condition
(A) There is one solution (b) and two solutions (c) (d) that cannot be determined
2 given that the lengths of three sides of a triangle are x2 + X + 1, x2-1 and 2x + 1 (x > 1), then the maximum angle is (b)
A.150° B.120° C.60° D.75°
3 in the acute angle △ ABC, if a = 2b is known, then the value range of a / B is (root 2, root 3)

1.a=?
Sine theorem a / sin60 ° = 4 / SINB, SINB = 2sqrt (3) / A,
Then 0

The relationship between the root and coefficient of mathematics in grade one of senior high school (Weida's theorem)
The root formula of quadratic equation AX ^ 2 + BX + C = 0 (a ≠ 0) is expressed by coefficient. If the quadratic equation has two real roots, we explore the relationship between the sum of two roots, the product of two roots and coefficient
………… Anyway, what is the main point of Veda's theorem, and what product of the two roots in it? What sum refers to X1 and X2?
Which two roots are X1 and X2?

X1 and X2 are ax ^ 2 + BX + C = 0 (a ≠ 0)
Weida's theorem is the relation between root and coefficient X1 + x2 = - B / a X1 * x2 = C / A

4 (x + 2) = 5 (x + 1) 2x of 3 = 42-2x of 2

4(x+2)=5(x+1)
4x+8=5x+5
5x-4x=8-5
x=3
2X of 3 = 42-2x of 2
2x/3=42-X/2
4x=252-3x
4x+3x=252
7x=252
x=252/7
x=36

-Two and two thirds + four and one half - five sixths + two and one sixth
The first number is preceded by a minus sign,

-1 / 2 + 2 / 2 + 6
=-2 + 2 / 3 + 4 + 1 / 2 + (- 5 / 6 + 2 + 1 / 6)
=-2 and 2 / 3 + 4 and 1 / 2 + 1 and 1 / 3
=-1 and 1 / 3 + 4 and 1 / 2
=3 and 1 / 6

To calculate "24 points" with four numbers "- 6, - 0.5, 2, 3", it is stipulated that: (1) each number must be used; (2) each number can only be used once (including the use of two and three numbers in the index); (3) the absolute value is considered to be unlimited; (4) the two formulas conforming to the "law of exchange" and "law of association" are considered to be the same formula; (5) the absolute value is considered to be the same formula If you know "negative index" and "prescription", then you should use it. (6) in order to cooperate with the teacher's marking, you should write the calculation steps carefully

（1）（-6+2）×3÷（-0.5）=（-4）×3÷（-0.5）=（-12）÷（-0.5）=24；（2）23×（-6）×（-0.5）=8×（-6）×（-0.5）=24；（3）2（-6）×（-0.5）×3=23×3=8×3=24；（4）|-6|×（|-0.5|×2+3）=6×（0.5×2+3）=6×4=24；（5）|（-6）2÷3÷（-0.5）|=|36÷3÷0.5|=24；（6）|（-6）+3÷（-0.5）|×2=|-6-6| ×2=12×2=24；（7）（-6）÷（-0.5）3÷2=（-6）÷（-0.125）÷2=48÷2=24；（8）|32÷（-0.5）|-（-6）=|9÷（-0.5）|+6=18+6=24；

Division of mathematics integral in grade one (6 * 10 ^ 5) ^ 2 / (3 * 10 ^ 2)
The answer in the book is 1.2 * 10 ^ 9. I don't know how to make it. Help me

36*10^10/3*10^2=12*10^8=1.2*10^9

-2 / 1, 3 / 2, - 4 / 3, - 6 / 5, 7 / 6. If this column is infinite, which two numbers are close to each other?

1 and - 1

4 / 5 × (1 / 6 + 0.75) + 0.8 × 1 / 12 (simple calculation)

17 + 5,1-6,27 + 0.75
=(8:23 17-6:23 27) + (5:4 1 + 0.75)
=1 and 13 / 23 + 6
=7 and 13 / 23

The simple calculation should be (1) 4 / (75% + 50% - 1) (2) 4.75 * 37.5% + 3 of 8 * 5.25 (3) 4 of 5 × 20% + 4 of 5

（1）4/（75%+50%-1）
=4÷25%
=16
(2) 4.75 * 37.5% + 3 / 8 * 5.25
=4.75x3/8+5.25x3/8
=(4.75+5.25)x3/8
=10x3/8
=15/4
(3) 4 / 5 × 20% + 4 / 5
=4/5x(1+20%)
=4/5x6/5
=24/25