Under what circumstances does weda's law fail? RT OK = = in fact, I've got the answer I want, but it seems to be true many times? The plural is also true
The quadratic coefficient of the equation is equal to 0, or the equation of non real solution
If Detta is equal to zero, what law should Veda's law satisfy
x1+x2=2x1=-b/a
X1 · x2 = the square of X1 = C / A
Can we solve the value of X 1-x 2 by means of Weida's law
OK. (x1-x2) square = (x1 + x2) square - 4x1 * X2, in the root, finally judge the positive and negative
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