The range of function y = X-2 / X-1. The range of function y = √ x + 1. The range of function y = (3x + 2) / (x-1) The range of y = 2x - √ (x-1)
It's not a heavy answer. If it is, I hope the landlord will adopt it
(1) y=(x-1-1)/(x-1)
=1-1/(x-1)
x-1≠0
1/(x-1)≠0
y≠1
(2)√x≥0
So y ≥ 1
(3)y=(3x-3+5)/(x-1)
=3+5/(x-1)
x-1≠0
5/(x-1)≠0
y≠3
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