Let 0 be greater than or equal to X and less than or equal to 2, find the maximum and minimum values of the function y = 4 ^ (x-1 / 2) - 3 * 2 ^ x + 5

Let 0 be greater than or equal to X and less than or equal to 2, find the maximum and minimum values of the function y = 4 ^ (x-1 / 2) - 3 * 2 ^ x + 5

Solution: from the title, 0 ≤ x ≤ 2
And the exponential functions are all increasing functions
The latter exponential function in the title is negative,
So this function is a decreasing function
So when x = 2, the function is the smallest, and its value is y = 4 ^ (2-1 / 2) - 3 * 2 ^ 2 + 5
=8-12+5
=1
When x = 0, the function is the largest, and its value is y = 4 ^ (0-1 / 2) - 3 * 2 ^ 0 + 5
=1/2-3+5
=5/2