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解:由題目有,0≤x≤2 且函數中的指數函數均為增函數 又題目中的後一個指數函數為負, 故此函數為减函數 故當x=2時函數最小,其值為y=4^(2-1/2)-3*2^2+5 =8-12+5 =1 當x=0時函數最大,其值為y=4^(0-1/2)-3*2^0+5 =1/2-3+5 =5/2
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