Given that a is a rational number and (a - √ 3) square = 7 + 4 √ 3, find the value of A fast

Given that a is a rational number and (a - √ 3) square = 7 + 4 √ 3, find the value of A fast

(a-√3)^2=7+4√3
a^2-2√3*a+3=7+4√3
a=-2

If three mutually unequal rational numbers can be expressed as either 1, a, a + B or 0, B, Ba, then a=______ ，b=______ ．

∵ three mutually unequal rational numbers are expressed in the form of 1, a + B, a, and 0, Ba, B. the numbers of these two arrays are equal. One of a + B and a is 0, and one of Ba and B is 1. However, if a = 0, Ba will be meaningless, and a ≠ 0 can only be a + B = 0, that is, a = - B Ba = - 1. Only b = 1, then a = - 1. So the answer is: - 1, 1

Let three unequal rational numbers be expressed in the form of 1, a + B, a, or 0, B / A, B, and then find the values of a and B

Because a! = B, a / B cannot be 1
Discuss the remaining possibilities
1)
a=0
a+b=a/b
b=1
It's obviously impossible
2)
a=a/b
b=1
a+b=0
We get a = - 1, B = 1