The image of the function y = 2x + 3x + 1 is symmetric with respect to the line x = 3. The corresponding analytic expression of the function is?

The image of the function y = 2x + 3x + 1 is symmetric with respect to the line x = 3. The corresponding analytic expression of the function is?

The vertex coordinates of the known function are (- 3 / 4, - 1 / 8), and an intersection point with the X axis is (- 1,0) ∵ the image of the function and the image of the known function are symmetric about x = 3 ∵ the vertex coordinates of the image of the function are (27 / 4, - 1 / 8) let the analytic expression of the function be y = a (x - 27 / 4) - 1 / 8 ∵ - 1,0

Let f (x) = 2x + 3x &; 1, if the image of function y = H (x) and the image of function y = F &; 1 (x + 1) are symmetric with respect to the straight line y = x, then H (3) = ()
f（x）=（2x+3）/（x-1）

You first draw a graph. The asymptote of F (x) is Y-axis and y = 2. The two functions are symmetric, so the asymptote is also symmetric. So the asymptote of H (x) is x-axis and x = 2, so h (x) = 2 / (X-2), so h (3) = 0.5

Given the function f (x) = x square (x ≥ 0), what is the value of F minus one (1 / 2)

1 / 4

Find the following function analytic formula: given that f (x + 1 / x) = the square of X + 1 / x, find f (x)

F (x + 1 / x)
=X & # 178; + (1 / x) &# 178;
=[x & # 178; + 2 + (1 / x) & # 178;] - 2
=(x + 1 / x) & # - 2
f(x)=x²-2