Let f (x) = one-half of the square of X × the X-Power of E (1) to find the monotone interval of F (x) (2) When x ∈ [– 2,2], the inequality f (x) < m is used to find the value range of real number M

Let f (x) = one-half of the square of X × the X-Power of E (1) to find the monotone interval of F (x) (2) When x ∈ [– 2,2], the inequality f (x) < m is used to find the value range of real number M


(1) Derivation f '(x) = 1 / 2xe ^ x + 1 / 2E ^ x = (1 / 2x + 1) e ^ x = 0
If e ^ x > 0, then X-2 increases monotonically
(2) When x ∈ [- 2,2], the function increases monotonically, so only m > F (2) = E & # 178; (not available, open interval)

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