Solution 3x + 20 = 6 (X-2) + 2 How to solve 3x + 20 = 6 (X-2) + 2? Please write every step

Solution 3x + 20 = 6 (X-2) + 2 How to solve 3x + 20 = 6 (X-2) + 2? Please write every step

3X+20=6X-12+2
3x-6x=-10-20
-3x=-30
x=10

（x+3）^2+(x+3)-42 a^3-24a^b+44ab^2 (a-b)^2-3(a-b)-10 5+6(a+1）+（a+1）^2 (x^2+3x)^2-8(x^2+3x)-20
(a^2+3a)^2-2(a^2+3a）-8
x^2-(a^2+b^2)x+a^2b^2
44ab ^ 2, - 10, (a + 1) ^ 2, - 20 (last number)
)

Using formula method to solve equation (x ^ 2 + 3x + 4) (x ^ 2 + 3x + 5) = 6

Let y = x ^ 2 + 3x + 4
y(y+1)=6
y^2+y-6=0
(y+3)(y-2)=0
(x^2+3x+7)(x^2+3x+2)=0
(x^2+3x+7)(x+2)(x+1)=0
x1=-2 x2=-1