Solve the equation x (2x + 1) (2x-1) - 2x (2x ^ 2-1) = 4

Solve the equation x (2x + 1) (2x-1) - 2x (2x ^ 2-1) = 4

x(2x+1)(2x-1)-2x(2x²-1)=4
x(4x²-1)-4x³+2x=4
4x³-x-4x³+2x=4
∴x=4

When a takes what value, the equation X-2 of X + X of X-2 + x ^ 2-2x of 2x + a = 0 has only one solution
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First of all, the equation is meaningful if x is not equal to 0 and 2. Then both sides of the equation are multiplied by x ^ 2-2x, and a new quadratic equation is obtained, that is, x ^ 2-x + 2 + A / 2 = 0 (*). The discriminant delta = 1-4 * (2 + A / 2) = - 7-2a, and the equation has only one solution, which shows one of the following two cases: 1) discriminant = 0, and the solution is not equal to 0 and 2 at this time

How to solve the cubic equation 3x ^ 3-8x ^ 2 + 6x-1 = 0, please write the specific process

Factorization 3x & sup3; - 3-8x & sup2; + 6x + 2 = 03 (X & sup3; - 1) - 2 (4x & sup2; - 3x-1) = 03 (x-1) (X & sup2; + X + 1) - 2 (4x + 1) (x-1) = 0 (x-1) (3x & sup2; + 3x + 3-8x-2) = 0 (x-1) (3x & sup2; - 5x + 1) = 0x-1 = 0,3x & sup2; - 5x + 1 = 0 x = 1, x = (5 - √ 13) / 2, x = (5 + √ 13) / 2

2X ^ 3 + 3x ^ 2 + 7x + 6 = 0 univariate cubic equation

2x^3+3x^2+7x+6=(x+1)(2x^2+x+6)
2x2+x+6>0
∴x+1=0
x=-1
The solution of the equation is - 1