The volume of an approximate conical funnel is 132 cubic centimeters, the bottom area is 44 square centimeters, and the height of the funnel is () cm

The volume of an approximate conical funnel is 132 cubic centimeters, the bottom area is 44 square centimeters, and the height of the funnel is () cm

The volume is equal to the bottom area times the height
So the height is 132 / 44 = 3cm

I want to make a trapezoidal funnel. The length and width of the upper opening is 900 * 600, and the lower opening is 40 * 40. The height of the funnel is 300. I want to know the area of its four sides?

（900+40）*300/2*2+（600
+40）*300/2*2 474000

Funnel surface area
We only know that the diameter of the funnel is 1200, the diameter is 800, and the height is 90

"Run, run, stop":
The funnel shape is a frustum (truncated cone)
The formula of the side area of the frustum is as follows:
M = Π L (R + R), M = area of the side of the cone, Π = circumference, l = generatrix, r = radius of small circle, r = radius of large circle
First, find bus 1 & sup2; = [(1200-800) / 2] & sup2; + 90 & sup2; = 48100, l = 219.3
Substitution formula: M = 3.1416 × 219.3 × (600 + 400) = 688.953 × 1000 = 688953
A: the surface area of the funnel is 688953 (square?). The unit is unclear
This formula is extracted from the manual of common metal materials
Good luck and goodbye