To make a conical funnel, its generatrix length is 20 cm, and its height should be () cm A. 2033B. 100C. 20D. 203

To make a conical funnel, its generatrix length is 20 cm, and its height should be () cm A. 2033B. 100C. 20D. 203


Let the height of cone be x, then the bottom radius is 202 − X2, and its volume is v = 13 π x (202-x2) (0 < x < 20), V ′ = 13 π (400-3x2). Let V ′ = 0, then the solution is X1 = 2033, X2 = - 2033 (rounding off). When 0 < x < 2033, V ′> 0; when 2033 < x < 20, V ′< 0; when x = 2033, V takes the maximum value



To make a conical funnel, its generatrix is 20 cm, and to make its volume the largest, what is its height?
If you want to make a 144m ^ 3 open rectangular box with a square bottom, if the cost per unit area is 4 yuan for the bottom and 3 yuan for the side area, how can you save the cost most.


If the side length of the bottom is x, then the height is 144 / x ^ 2; if the cost is y, then the equation y = 4x ^ 2 + (4 * x) * (144 / x ^ 2) * 3 can be formulated and solved



To make a conical funnel, its generatrix length is 20 cm, and its height should be () cm
A. 2033B. 100C. 20D. 203


Let the height of cone be x, then the bottom radius is 202 − X2, and its volume is v = 13 π x (202-x2) (0 < x < 20), V ′ = 13 π (400-3x2). Let V ′ = 0, then the solution is X1 = 2033, X2 = - 2033 (rounding off). When 0 < x < 2033, V ′> 0; when 2033 < x < 20, V ′< 0; when x = 2033, V takes the maximum value