The fuel consumption of a car is 10L for every 100km. Given that the density of 93 oil used by the car is 0.75 × 103kg / m3, the fuel consumption of the car for 100km is 0.75 × 103kg / m3

The fuel consumption of a car is 10L for every 100km. Given that the density of 93 oil used by the car is 0.75 × 103kg / m3, the fuel consumption of the car for 100km is 0.75 × 103kg / m3

1L=0.001m3 10L=0.01m3
Mass m = density * volume = 0.75 × 103kg / m3 * 0.01m3 = 7.5kg

The performance of a certain type of car will be tested by a professional course teacher. He drives the car at a constant speed of 72km / h for 10min and consumes 1.2kg of gasoline. The resistance F of the car at constant speed is 1.2 × 103n. (calorific value of gasoline q = 4.6 × 107j / kg). According to the above information, we can calculate: (1) how much work does the car do during the test period? (2) What is the useful power of the car during the test time? (3) What is the efficiency of the car in the test time? And the cause of energy loss is analyzed (write two)

(1) During the test period, the total work of the vehicle is: wtotal = q discharge = QM = 4.6 × 107j / kg × 1.2kg = 5.52 × 107j; (2) the useful power of the vehicle during the test period is: PST = FV = 1.2 × 103n × 20m / S = 2.4 × 104w; (3) the useful work of the vehicle during the test period is: wtotal = 2.4 × 104w × 600s = 1.44 × 107j; the efficiency of the vehicle during the test period is: η = wtotal = 1.44 × 107j5.52 × 10 The reasons of energy loss are: ① the gasoline is not completely burned; ② the exhaust gas takes part of the heat away. A: (1) the work done by the car during the test period is 5.52 × 107j; (2) the useful power of the car during the test period is 2.4 × 104w; (3) the efficiency of the car during the test period is 26%, and the energy loss is: the gasoline is not completely burned; the exhaust gas takes part of the heat away Heat

A car runs at a constant speed of 72km / h for 10min. The consumption of gasoline is 1.2kg
A car runs at a constant speed of 72km / h for 10min. It consumes 1.2kg of gasoline. When the car runs at a constant speed, its traction force F = 1200n, and its calorific value Q = 46000000j / kg. Q: (1) what is the power consumed outside the car during this period of time (that is, the heat released by the complete combustion of gasoline in a wonderful time)?

(1) Heat released by complete combustion of automobile q = QM = 4.6 * 10 ^ 7 * 1.2 = 5.52 * 10 ^ 7 J
Power consumed by the vehicle P = q / T = 5.52 * 10 ^ 7 J / (60s * 10) = 9.2 * 10 ^ 4 W