If a certain amount of oxygen is contained in a steel cylinder, and 1 / 3 of it is used in one welding, the mass of the remaining oxygen in the cylinder is the same as the original______ Times the original density______ Times

If a certain amount of oxygen is contained in a steel cylinder, and 1 / 3 of it is used in one welding, the mass of the remaining oxygen in the cylinder is the same as the original______ Times the original density______ Times

Let v be the volume of the oxygen cylinder, m be the mass of residual oxygen, m be residual = ρ oxygen (1-13v) = 23m; ∵ the volume of oxygen remains unchanged ∵ the density of residual oxygen is ρ be residual = m be residual v = 23mv = 23 ρ oxygen

The oxygen density in the cylinder is ρ. When one third of the oxygen in the cylinder is used, what is the remaining oxygen density?
rt...

When ρ = m / V, V remains unchanged, m becomes the original 2 / 3, and the residual density is 2 / 3 ρ

The density of oxygen in a steel cylinder is 6kg / M & sup3;, and the density of residual oxygen is ()

Let the original mass be m and the volume be v
The density of residual oxygen is as follows:
m*(1-2/3)/v=1/3p=6kg/m³/3=2kg/m³