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The density of oxygen contained in a steel cylinder is 8 kg / m3. If one quarter of the oxygen is used for one welding, the density of the remaining oxygen in the cylinder is 0
If the density is constant, the volume is reduced by a quarter. Density = mass / volume. Mass and volume use 1 / 4 at the same time, so the density is constant. The problem is not very clear. Maybe you want to ask volume
There is an oxygen bottle in the hospital, its volume is 10dm3, and the density is 5kg / m3. 10g oxygen is used for a certain rescue
The density of the remaining gas in the bottle is
The original oxygen density is 5kg / m3 = 5g / dm3
The original oxygen mass = density × volume = 5 × 10 = 50g
10 g is used and 40 g is left
The volume of oxygen is always equal to 10 DM3 of the oxygen cylinder
So the residual oxygen density is 40 △ 10 = 4G / dm3 = 4kg / m3
There is an oxygen cylinder in the hospital with a volume of 10 DM3 and a density of 2,5 kg / m3. The oxygen used for one rescue is 5 g, and the remaining oxygen density is 2 kg / m3. Why?
1 kg/m^3= 1 g/dm^3
Initial oxygen mass = 2.5 * 10 = 25 g
After that, oxygen mass = 20 G
Density = 20 / 10 = 2 kg / m ^ 3
The remaining oxygen density is 2 kg / m3
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