What is 23 times 1? &What is 23 times 1? The number of a is 1.6 times that of B, and the ratio of a to B is? Given that the ratio of AB to BC is 2 to 3, then the area ratio of triangle abd to triangle DBC is? come on. ↖ (^ω^) ↗

What is 23 times 1? &What is 23 times 1? The number of a is 1.6 times that of B, and the ratio of a to B is? Given that the ratio of AB to BC is 2 to 3, then the area ratio of triangle abd to triangle DBC is? come on. ↖ (^ω^) ↗


23 times (1 / 23) equals 1
The number of a is 1.6 times that of B, and the ratio of a to B is (8:5)
It is known that the ratio of AB to BC is 2 to 3, then the area ratio of triangle abd to triangle DBC is (4:9)



How many times how many is equal to 23 and 46


2 by 11.5 2 by 23



What's 74 times 74 out of 75


74 * (74 / 75) = 5476 / 75 is about 73



A. The distance between two places B is 480 kilometers. A local train starts from a and travels 60 kilometers per hour, while an express train starts from B and travels 65 kilometers per hour. If two trains leave at the same time and travel in the same direction, the express train is behind the local train and catches up with the local train after X hours, then the De's equation is (as long as the equation, explain the reason)
Party A and Party B start from two places 60 kilometers apart and walk in opposite directions. Party A walks at a speed of 6 kilometers per hour. Party B rides a bicycle and meets each other in three hours to find the speed of Party B. If Party A and Party B walk in the same direction at the same time, and Party A is in the front and Party B is in the back, how many hours will it take for Party B to catch up with Party A? (equation, solution,)
10 points for each correct answer


1
65x-60x=480
65, speed of express train; X, travel time of express train
60, slow speed; X, slow travel time
65x express journey, 60x local journey. The difference between the two results in the original distance of the two vehicles
two
1) Let B speed be x km / h
6×3+6x=60 x=7
2) Let's catch up with B in Y hours
7y-6y=60 y=10
Is this the problem of junior high school?



1. In the RT triangle ABC, ∠ C = 90 ° SINB = 3 / 5, point D is on the BC side, and ∠ ADC = 45 ° DC = 6, find the tangent of ∠ bad. (let me describe the figure of this problem, first draw a RT triangle ABC, take a point D on the BC side, connect AD)
2. In triangle ABC, ∠ C = 90 °, a + B = 2 + 2 √ 3, C = 4, then ∠ a=_____
If you find it troublesome to write the steps,
Please tell me your thoughts,


Graphic description: make de perpendicular to ad, e perpendicular to foot
Because ∠ ADC = 45 ° CD = 6
So AC = CD = 6
And SINB = 3 / 5
So AB = 10, BC = 8
Then DB = 2
The same can be obtained
DE=1.2 AE=8.4
So tan ∠ bad = de / AE = 1 / 7
2 questions
For filling in the blanks, we should be flexible~
According to the meaning of the title, a triangle is a right triangle
Because a + B = 2 + 2 √ 3, C = 4
So, we can dismantle it
A = 2, B = 2 √ 3, or a = 2 √ 3, B = 2
Then cosa = 1 / 2, or cosa = √ 3 / 2
That is, a = 60 ° or a = 30 °



-a³+2b³-3ab+2=-_____ =2-a³-____ .
If A-B = 4, B-C = 1, C-D = - 2, then A-D=____ .
Then, if sup + 2 x + 6-x=_____ .


-a³+2b³-3ab+2= - (a³-2b³+3ab-2)=2-a³-(3ab-2b³)
If A-B = 4, B-C = 1, C-D = - 2, then A-D = (a-b) + (B-C) + (C-D) = 4 + 1-2 = 3
If 2x & sup2; - 6x + 1 = 0, then 6 + 3x-x & sup2; = (1 / 2) (12 + 6x-2x & sup2;) = (1 / 2) [12 - (2x & sup2; - 6x)] = (1 / 2) [12 - (- 1)] = 13 / 2



Junior high school mathematics problems, to solve ah
1. Given that equation (2a-7b) x + (3a-8b) = 8x + 10 holds for all real numbers x, find the value of A.B


It holds for all real numbers X
Then the coefficient of X and the constant are equal respectively
2A-7B=8 (1)
3A-8B=10 (2)
(2)×7-(1)×8
21A-16A=70-64
5A=6
A=6/5
B=(2A-8)/7=-4/5



The difference between 1 fraction and integral
2. If a truck delivers goods up the mountain with an uphill speed of X km / h and a downhill speed of Y km / h, the average speed of the truck is km / h
3 given a + B 1 / 2 = a 1 / 2 + B 1 / 2, find the value of B of a + a of B
Given 1-x / 1 + x = 1 + Y / 1-y, find the square of (2 + x) (2 + y) + X
What is zenggen
Xiao Wang rides his bicycle at an average speed on the ring road. Every six minutes, a bus runs backward from the opposite side, and every 30 minutes, another bus runs forward from the back. If the bus runs at an average speed and does not remember the time when passengers get on and off, how many minutes does the bus leave at the bus stop?
A new coating is prepared with a coating with a value of 100 yuan and a coating with a value of 240 yuan. The selling price per kilogram of the new coating is 3 yuan less than that of a coating and 1 yuan more than that of B coating


1. Monomials and polynomials are called integers
The numerator and denominator are integral, and the formula with letters in the denominator is called fraction
2. Let the total distance be s, 2XY / x + y
3. 1 / A + B = 1 / A + 1 / b = a + B / AB, then (a + b) ^ 2 = AB, B / A + A / b = (a ^ 2 + B ^ 2) / AB, [(a + b) ^ 2-2ab] / AB = - AB / AB = - 1
4、
5. The root that can make the simplest common denominator of the fractional equation zero is its increasing root. If the equation has no original solution, there is no increasing root
6. Let the speed of Xiaoming be VA, the speed of bus be VB, and the distance between two cars be s
s/(va+vb)=6,s/(vb-va)=30
va=2/3*vb,t=10min
7. The price of the new coating is x yuan / kg
100/(x+3)+240/(x-1)=340/x
The solution is: x = 17



If a line L passes through three different points a (a, b), B (B, a), C (A-B, B-A), then the line L passes ()
A. The second and fourth quadrants B. the first, second and third quadrants C. the second, third and fourth quadrants D. the first, third and fourth quadrants


Let the analytic formula of the straight line be y = KX + C, and substitute a (a, b), B (B, a), C (A-B, B-A) into b = AK + Ca = BK + CB − a = (a − b) K + C. the solution is k = - 1, C = 0, | y = - x, and the image passes through the second and fourth quadrants, so a



According to statistics, the total throughput of domestic and foreign trade of Lianyungang port in 2002 and 2003 were 33 million tons and 37.6 million tons respectively, of which the throughput of foreign trade and domestic trade in 2003 increased by 10% and 20% respectively compared with 2002. (1) try to determine the throughput of foreign trade and domestic trade in 2002; (2) the target of the throughput of domestic and foreign trade of Lianyungang port in 2004 is that the total throughput of domestic and foreign trade is not less than 42 million tons, of which the proportion of foreign trade throughput is not low It is estimated that the domestic trade throughput in 2004 will increase by 10% compared with that in 2003. In order to achieve the above goal, how many million tons should the foreign trade throughput in 2004 increase at least compared with that in 2003?


(1) Suppose the throughput of domestic trade and foreign trade in 2002 are respectively X and Y ten thousand tons. Then x + y = 3300 x (1 + 20%) + y (1 + 10%) = 3760 (2 points) the solution is x = 1300, y = 2000. Answer: the throughput of domestic trade and foreign trade in 2002 are respectively 13 million tons and 20 million tons. (4 points) (2) suppose the throughput of foreign trade in 2004 is increased compared with that in 2003