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How much is 35 times 75? How much is 46?
35*75=2625,2625*26=120750
How much is 96 times 35%
33.6
34 * 36 simple operation
=(35+1)(35-1)=35^2-1=1225-1=1224
If any term of an equal ratio sequence of positive numbers is equal to the sum of the following two terms, what is the common ratio?
I want to understand
Let the first term be a and the common ratio be Q,
All are positive numbers,
So a > 0, Q > 0
aq^n=aq^(n+1)+aq^(n+2)
q^n(q^2+q-1)=0
Because Q > 0
So Q ^ n is not equal to 0
So Q ^ 2 + Q-1 = 0
q>0
So q = (- 1 + √ 5) / 2
What is the common ratio q if all the items of an equal ratio sequence are positive and any of its items are equal to the sum of the following two items
From the theme
a1*q^(n-1)=a1*q^n+a1*q^(n+1)
Because A1 is not equal to 0, and Q is not equal to 0
So we can make an appointment
Let 1 = q + Q ^ 2
The solution is q = [(radical 5) - 1] / 2 (the other negative radical has been discarded)
If any one of the items of an equal ratio sequence is equal to the sum of the following two items, then its common ratio is ()
A. − 1 − 52b. − 1 + 52C. 1 + 52d. − 1 − 52 or − 1 + 52
From the meaning of the title, we can get an = an + 1 + an + 2, ∵ an + 1 = anq, an + 2 = anq2, ∵ an = anq + anq2, ∵ an > 0, ∵ 1 = q + Q2, and the solution is q = − 1 ± 52, ∵ Q > 0, ∵ q = 5 − 12
If any term is equal to the sum of the following two terms, then the common ratio is?
If any term is equal to the sum of the following two terms, then the common ratio is -?
Since it is an equal ratio sequence, let it be a, AQ, AQ ^ 2, AQ ^ 3 And give us the condition that any term is equal to the sum of the following two terms. For example, take the first three terms and list the formula according to the condition: a = AQ + AQ ^ 2, reduce a, that is, Q ^ 2 + Q-1 = 0, and solve Q. finally, note that it is a positive number sequence, that is, q is positive, and remove the negative
What is the common ratio if all the items of an equal ratio sequence are positive and any of its items are equal to the sum of the following two items?
Actually, it's very simple
Let the formula of equal ratio sequence be AQ ^ (n-1)
aq^1+aq^2=aq^3
The equation is solved
1+q=q^2
Q can be solved by formula method
Bring in the formula and you can pull
The answer is:
The formula of equal ratio sequence: 2 / (1 + radical 5) a or 2 / (1-radical 5) a, where a is greater than zero
If the sum of the three positive numbers in the arithmetic sequence is equal to 15, and the three numbers are added with 1, 3 and 9 to form the arithmetic sequence, then the product of the three numbers is equal to 15______ ．
Let the three positive numbers of the arithmetic sequence be A-D, a, a + D respectively. According to the meaning of the problem, we get A-D + A + A + D = 15, and the solution is a = 5 ∵ three numbers are added with 1, 3, 9 respectively, and then the arithmetic sequence is ∵ 6-D, 8, 14 + D ∵ 64 = (6-D) × (14 + D) ∵ D is positive, so d = 2 ∵ three numbers are 3, 5, 7 ∵ the product of three numbers is equal to 105, so the answer is 105
Let n be a positive integer, and insert n positive numbers between 1 and N + 1, so that the N + 2 numbers form an equal ratio sequence, then what is the product of the n positive numbers inserted?
Can you tell me where I can find the answer analysis website of GCT in other years,
Open it (don't save it), question 14 is, there's an answer,
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