The solution of 5x square - 8x + 2 = 0 by public trial method I don't understand the following answer. I hope someone is answering. I hope it's not as complicated as the following

The solution of 5x square - 8x + 2 = 0 by public trial method I don't understand the following answer. I hope someone is answering. I hope it's not as complicated as the following

x=(-(-8)±√((-8)^2-4*5*2))/2*5
=(8±√(64-40))/10
=(8±√24)/10
=((8±2√6)/10
=(4±√6)/5
x1=(4+√6)/5
x2=(4-√6)/5

Given the equation x Λ 2-3x + K + 1 = 0, try to add a condition so that the product of its two is 2. What is one root of the equation?

k=1
Two 1,2

What is the root of equation 3x ^ 2-9 = 0?
I'm not sure if it's the root sign 3 now?

3x^2-9=0
3x^2=9
x^2=3
X1 = root 3
X2 = - root 3
yes

Finding two roots of the equation 2x square-3x-10 = 0

b^2-4ac=89
X1 = (3-radical 89) / 4
X2 = (3 + radical 89) / 4
Using formula method
x=[-b±√(b^2-4ac)]/2a

1. By changing the quadratic equation 2x-3y = 6 into the form of y = KX + B, we get K=
2. If the product of (x-a) (2x + 1) does not contain a linear term of X, then the value of a is?

1,2x-3y=6
-3y= 6-2x
y= (6 - 2x)/(-3)
y=-2 + 2/3 x =2/3 x - 2,
So k = 2 / 3, B = - 2;
2,(x-a)(2x +1)= 2x^2 - 2x*a + x - a
It is assumed that the product of (x-a) (2x + 1) does not contain a linear term of X,
So the coefficient of the first term of X is 0,
That is - 2x * a + x = 0
-2x * a = -x
a = 1/2

When x = - 3, the values of the functions y = x + K and y = kx-1 are equal, then the value of K is in the form of y = KX + B which transforms the quadratic equation 3y-2x = 12 into y = KX + B
Urgent! Or I'll be scolded tomorrow!

Analysis: when x = - 3, the values of function y = x + K and y = kx-1 are equal, which means that "function value Y" is equal, that is, x + K and kx-1 are equal. From the meaning of the problem, we get the solution of - 3 + k = - 3K-1: k = 1 / 2, shift term: 3Y = 2x + 12, transform coefficient is 1: y = 1 / 3 (2x + 12), that is, y = 2x / 3 + 4

If we change the quadratic equation 2x + 3Y = 4 to y = KX + B, what is the value of K / b

2x+3y=4
3y=-2x+4
y=-2x/3+4/3
k=-2/3
b=4/3
k/b=(-2/3)/(4/3)=(-2/3)(3/4)=-1/2.

Change the quadratic equation 2x + 3Y = 25 into the form of y = KX + m, and write the value of K, M

2x+3y=25
3y=-2x+25
y=-2x/3+25/3
So k = - 2 / 3, M = 25 / 3

Change the quadratic equation 2x + 3Y = 25 into the form of y = KX + m and write the value of K, M

2x+3y=25
3y=-2x+25
x=-2x/3+25/3
k=-2/3,m=25/3

If x + y = 2, xy = - 8, find the square of the algebraic formula 3x and the square of y-18xy

3x ^ 2y-18xy ^ 2 = 3xy (x-6y) = 3 (- 8) (x-6y) = - 24 (x-6y) (*) (X-Y) ^ 2 = (x + y) ^ 2 - 4xy = 4-4 (- 8) = 36 = > X-Y = 6 or - 6x + y = 2; when X-Y = 6, x = 4; y = > (*) = - 24 (4 + 12) = - 384... Ans (1) x + y = 2; when X-Y = - 6, x = - 2; y = 4 = > (*) = - 24 (- 2-24) = 624... Ans (2)