If the square of 9x + XY + my is a complete square, then M =?

If the square of 9x + XY + my is a complete square, then M =?

Let the square of 9x + XY + my be the square of (a + b)
Then there are: (a + b) square = a square + 2Ab + b square
The square of a + 2Ab + B = the square of 9x + XY + my
According to the principle of equality, there are:
A's Square = 9x's Square X's Square = A's Square / 9
2ab＝xy
Square of B = square of my, square of y = square of B / M
There are: 4 a squared B squared = x squared y squared = a squared / 9 * B squared / M
4=1/9m
m=1/36
So m = 1 / 36

If the square of 9x + MXY + 16y is a complete square, then M is a constant=

If 9x ^ 2 + MXY + 16y ^ 2 is a square form
It's (3x ± 4Y) ^ 2
m=±24

The square of 9x - the square of 16y
-The third power of square a and square B of 1 + 16x-the square of 4A multiplied by B

The square of 9x - the square of 16y
=（3x+4y）(3x-4y)
-Square of 1 + 16x
=(4x+1)(4x-1)
The third power of a's Square B-the square of 4A multiplied by B
=a²b(b²-4)
=a²b(b+2)(b-2)
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