Solving the equation in the complex range |z|+z=6+2i Solving the equation in the complex range

Solving the equation in the complex range |z|+z=6+2i Solving the equation in the complex range

Let z = a + bi
Bring in the solution and get AB value

On the solution equation of complex number
(z+1)^3=8(z-1)^3

(z+1)³-[2z-2)]³=0
(-z+3)[(z+1)²+2(z+1)(2z-2)+(2z-2)²]=0
(-z+3)(7z²-6z+3)=0
According to the product of two complex numbers is 0, at least one complex number is 0
So - Z + 3 = 0 or 7z & # 178; - 6Z + 3 = 0
From - Z + 3 = 0 to Z = 3
7z²-6z+3=0
Let z = a + bi be substituted
We get 7a-178; + 14abi-7b-178; - 6a-6bi + 3 = 0
7a²-7b²-6a+3+(14ab-6b)i=0
7A & # 178; - 7b & # 178; - 6A + 3 = 0 and 14ab-6b = 0
From 14ab-6b = 0, (14a-6) B = 0, B = 0 is meaningless, so a = 3 / 7
Substituting a = 3 / 7 into the first equation, we get b = 3 √ 2 or B = - 3 √ 2
So z = 3 or Z = 3 / 7 + 3 √ 2I or 3 / 7-3 √ 2I

To solve the equation | Z ^ 2 | + (conjugate complex number of Z + Z) I = 2-4i / 3-I in the complex range

Let z = x + Yi (x, y ∈ R)
|Conjugate complex number of Z ^ 2 | = x ^ 2 + y ^ 2 Z + Z = 2x
2-4i/3-i=(2-4i)(3+i)/10=1-i
x^2+y^2 =1 2x=-1
x=-1/2 y=±√3/2
z=-1/2+√3i/2 z=-1/2-√3i/2

How to solve the equation 9x-1.2x0.8 = 5x

9x－1.2x0.8=5x
9x－0.96=5x
9x-5x=0.96
4x=0.96
x=0.24

Solving binary linear equation x ^ 2-7x = 6, (2x + 1) ^ 2-x ^ 2 = 0

X ^ 2-7x = 6 is calculated by the root formula, a = 1, B = - 7, C = - 6
(2x+1)^2-x^2=0
Use the square difference formula: (2x + 1 + x) (2x + 1-x) = 0
(3x+1)(x+1)=0
x1=-1/3 x2=-1

Is the square of X + y-6 = 2x a quadratic equation of two variables

No, binary quadratic

Quadratic equation of X + 2x + 2 = 8x + 4

x^2+2x+2=8x+4
x^2-6x=2
(x-3)^2=11
x-3=±√11
x=3±√11

The square of (X-2) - 18 = 0 to solve the quadratic equation of two variables

x-2= ±√18
x = ±√18 + 2
x = ±3√2 + 2

Is the square of x = 0 a quadratic equation of two variables

Of course
As long as the highest power of the unknown is 2 and there is only one unknown

Solving the quadratic equation of 2 / 2 x-4 [X-1] = 0

Multiply both sides by two
x^2-8x+8=0
x^2-8x+16-8=0
(x-4)^2-8=0
(x-4-2√2）(x-4+2√2）=0
x1=4+2√2
x2=4-2√2