When x = 2013, y = 2014, the value of the algebraic formula (x / Y-Y / x) △ X-Y / X is

(x/y-y/x)÷x-y/x
=(x²-y²）/xy÷(x-y)/x
=(x+y)(x-y）/xy÷(x-y)/x
=(x+y)/y
=(2013+2014)/2014
=4027/2014
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It is known that X1 and X2 are the two real roots of the equation (X-2) (x-m) = (P-2) (P-M) about X. (1) find the value of X1 and X2; (2) if X1 and X2 are the lengths of the two right sides of a right triangle, when the real numbers m and P satisfy what conditions, the area of the right triangle is the largest? And the maximum value is obtained

(1) The original equation is changed as follows: X2 - (M + 2) x + 2m = P2 - (M + 2) P + 2m, ｜ x2-p2 - (M + 2) x + (M + 2) P = 0, (X-P) (x + P) - (M + 2) (X-P) = 0, that is, (X-P) (x + p-m-2) = 0, ｜ X1 = P, X2 = m + 2-P; (2) according to (1), the area of right triangle is 12x1x2 = 12p (...)

We know the equation x square - (m-2) x-4 / m square = 0 about X. if the two real roots of the equation satisfy | x2 | = | x1 | = 2, we find the value of M and the corresponding formula
Wrong number. Sorry
Two real roots satisfy | x2 | = | x1 | + 2

Δ = (m-2) ^ 2-4 * (- m ^ 2 / 4) = (m-2) ^ 2 + m ^ 2 > 0, then the two real roots must not be equal
|X2 | = | x1 | = 2 (= 2 condition may be wrong?), then X1 + x2 = m-2 = 0, M = 2
x1=1,x2=-1

It is known that the equation (m-2) x ^ 2 + 4x + m ^ 2-4m = 0 about X has a root of 1, so we can find the value of M

Substitute x = 1 into the equation
m-2+4+m^2-4m=0
m^2-3m+2=0
(m-1)(m-2)=0
M = 1 or M = 2

When x = 2013, y = 2014, the value of the algebraic formula (x / Y-Y / x) △ X-Y / X is