|X-Y + 1 | and | x + y-2013 | are opposite numbers. Find the value of (x - y) (x + y) |X-Y + 1 | and | x + y-2013 | are opposite to each other- y) The value of (x + y)

|X-Y + 1 | and | x + y-2013 | are opposite numbers. Find the value of (x - y) (x + y) |X-Y + 1 | and | x + y-2013 | are opposite to each other- y) The value of (x + y)

According to the meaning of the title:
x-y+1=0,x+y-2013=0
Then X-Y = - 1, x + y = 2013
So (X-Y) (x + y) = (- 1) x2013 = - 2013
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It is known that 2012 (x + y) 2 and X − y − 420132 are opposite numbers, and the value of x-y2 is obtained

∵ 2012 (x + y) 2 and X − y − 420132 are opposite numbers, ∵ 2012 (x + y) 2 + X − y − 420132 = 0, ∵ x + y = 0x − y − 4 = 0, the solution is x = 2Y = − 2, so x-y2 = 2 - (- 2) 2 = 2-4 = - 2

If | x-2013 | and | y-13 | are opposite numbers, find the value of X + 2Y / X-Y

This kind of topic x is equal to 2013, y is equal to 13, don't consider other
If we change the topic, such as: | X-12 | and | y-1000 | are opposite numbers, find the value of X + 2Y / X-Y, then x = 12, y = 1000
Then we substitute the value of X and Y into the title: x + 2Y / X-Y
=2013+2*13/2013-13
=2013+26/2000
=2039/2000
=1.0195