The minimum integer value of X that makes the value of the algebraic formula 4x-1.5 greater than 3x + 5 is

The minimum integer value of X that makes the value of the algebraic formula 4x-1.5 greater than 3x + 5 is


4x-1.5>3x+5
4x-3x>5+1.5
x>6.5
Then the minimum value of X is x = 7



Solution equation: (21-5x) / 2 = x 4 (x-3) = 2x


(21-5x)/2=x 4(x-3)=2x
21-5x =2x 4x-12=2x
21 =7x 4x-2x=12
x=3 x=6



How to solve the equation of 2x + 14.8 = 21


2x+14.8=21
2x=21-14.8
2x=6.2
x=3.1