The product obtained by multiplying the square of X + ax + B by X + 3 is the third power of X + 2x + 33?
Square of X + ax + B times x + 3 = x ^ 3 + (3 + a) x ^ 2 + (3a + b) x + 3B
So 3 + a = 0,3a + B = 2,3b = 33
So a = - 3, B = 11
So AB = - 33
Given that x = - 4, y = quarter, find the value of the quadratic power of (x times the n power of x) times the quadratic power of (n + 1 power of Y)
So urgent, solve, complete process, seek master solution
The value of the quadratic power of (x times the nth power of x) times the quadratic power of (n + 1 power of Y)
=x^(2n+2)*y(2n+2)
=[(xy)^2]^(n+1)
=[(-1)^2]^(n+1)
=1^(n+1)
=1
[questions are welcome]
Given that the nth power of x = 5, the nth power of y = 3, find the value of the nth power of (x square, y) square
The nth power of x = 5
The nth power of y = 3
The nth power of (x square, y) square
=(x^2y)^2n
=x^4n*y^2n
=5^4*3^2
=625*9
=5625