Valence layer electron logarithm = -+——

Valence layer electron logarithm = -+——

The logarithm of σ bond formed by central atom plus lone electron pair

How can HCN be calculated as SP hybrid by using the formula of valence layer electron logarithm
（4+1+5）/2=5

The central atom is C, and the valence electron number is + 1 for each h and halogen as coordination atoms. The O group elements do not provide valence electrons, but the N group elements coordinate with - 1. Therefore, the valence layer electron logarithm is (4 + 1-1) / 2 = 2, which is sp hybrid

Operation of exponent and logarithm
81 ^ 3 / 4 32 ^ - 2 / 5 (- 32) ^ 3 / 5 (0.001) ^ 2 / 3 which can help me to write down the formula

81^3/4 =(3^4)^3/4=3^3=27
32^-2/5 =(2^5)^-2/5=2^-2=1/4
（-32）^3/5=((-2)^5)^3/5=(-2)^3=-8
（0.001)^2/3=(10^-3)^2/3=10^-2=0.01

Law of logarithm

logaM+logaN=logaMN
logaM-logaN=loga（M/N）
logaM^N=NlogaM
loga^M（b^N）=（M/N〉logab

What is the logarithm of the base

When the base is greater than 0 and the inequality is 1,
So the logarithm of the base is 1
(note prerequisites)

Can the base of logarithm be negative?
I see that there is no negative base in the logarithmic equation in the book, and it is said that it should be greater than 0 and not equal to 1. Then why can I calculate the answer to this logarithmic equation?
prove:
Why is this check not correct?

logx(2x+3)=2
General solution
Take the exponent of X
2x+3=x^2
X = 3 or x = - 1
(of course it's not right for you to use x = - 3 generation)
And then it's going to round off - 1. Why?
From this point of view
On the left side of the equation is
logx(2x+3)=log-1(1)
You can say (- 1) ^ 2 = 1, you can say (- 1) ^ 4 = 1 and so on
So the value of log-1 (1) function is not unique and does not conform to the definition of function
Further consideration: the base is negative, such as - 2
Log-2 (3) =? Is it log2 (3)? No, the two answers are almost irrelevant
(- 2) ^ x = 3 the solution of X is not a real number
Try other numbers, and we find that log-2 (x) is discontinuous and irregularly distributed in the domain of real numbers, so the logarithm base has no negative value
The case that the base is not equal to 1 is very simple: any power of 1 is 1
If the true number is 1, then the function value is not unique; if the true number is not 1, then the function has no solution

What is the logarithm of base 2 and 6? How to calculate it? What is the formula for changing base and how to calculate it?
log(2)6=lg6/lg2
Why change like this?
lg6/lg2=(lg2+lg3)/lg2
How did this change?
Now chenyeceye,

log(2)6=lg6/lg2=(lg2+lg3)/lg2=1+lg3/lg2=2.585
The formula of changing bottom: log (2) 6 = log (x) 6 / log (x) 2 {the one with brackets is the bottom)
Among them, LG2 and Lg3 are constants and require memory. Lg3 = 0.477
lg2=0.301
I've sent you a message

Why is the logarithm of the base 1
ditto..

Logarithm is to know the base number and the result and find the exponent
For example, the x power of a is equal to B. in the logarithmic form, the logarithm of a as B is equal to X,
Thus, a is the base, and the logarithm of a is equal to 1

Xiaoqiang makes a house for an injured bird. The house is three fifths of a meter long, two fifths of a meter wide and one third of a meter high. How much space does the house occupy?

The space occupied by the house is the volume of the house
Volume = 3 / 5x2 / 5x1 / 3 = 2 / 25m3

How many square meters is a rectangular room 2.3 meters long, 1.3 meters wide and 1 meter high on the ground

There is no rectangle in the room. If it is a cuboid, the volume of the room is s = ABH
=2.3x1.3x1
=2.99 (M3)
If we calculate the floor area: S = ab
=2.3x1.3
=2.99 (M2)
If we calculate the surface area: S = abx6
=2.3x1.3x6
=17.94 (M2)