Given x = 1175, y = 2522, then the value of (x + y) 2 - (X-Y) 2 is equal to () A. 16B. 13C. 23D. 58

Given x = 1175, y = 2522, then the value of (x + y) 2 - (X-Y) 2 is equal to () A. 16B. 13C. 23D. 58

(x + y) 2 - (X-Y) 2, = (x + y + X-Y) (x + Y-X + y), = 2x · 2Y, = 4xy, when x = 1175, y = 2522, the original formula = 4 × 1175 × 2522 = 23

1. Calculate (1) 2a-3 (3a-2b) 2 (a + 2b) (2) (xsquare - 2XY + ysquare) - (xsquare + 2XY + ysquare)
1. Calculation
⑴2a-3(3a-2b)2(a+2b)
(2) (xsquare - 2XY + ysquare) - (xsquare + 2XY + ysquare)
(3)5a+3[2b-3(a﹣b+2c）﹣（b+c）]
(4) (- 3 / 4 square) square

1.2a-3(3a-2b)2(a+2b)=2a-(9a-6b)(2a+4b)=2a-(18a^2-12ab+36ab-24b^2)=2a-18a^2+12ab-36ab+24b^2=2a-18a^2-24ab+24b^2
2.(x^2-2xy+y^2)-(x^2+2xy+y^2)=x^2-2xy+y^2-x^2-2xy-y^2=(-4xy)
3.5a+3[2b-3(a﹣b+2c)-(b+c)]=5a+[6b-9(a-b+2c)-3(b+c)]=5a+6b-9a+9b-18c-3b-3c=12b-4a-21c
4.[(3a^2)/(-4)]^2×[(3a)^3/4]^2=[(81a^5)/(-16)]^2=(6561a^10)/196

1.3(x-y)^2+4(x-y)-4 2.2（2m-n)^2 +7（2m-n)-15 3.x^2-2xy+10x-10y+25 4.(x-y)^2-2x+2y
Group factorization
I'm in a hurry

1. 3(x-y)^2+4(x-y)-4 =[3(x-y)-2]*[(x-y)+2]=(3x-3y-2)(x-y+2).2. 2（2m-n)^2 +7（2m-n)-15 =[2(2m-n)-3]*[(2m-n)+5]=(4m-2n-3)(2m-n+5).3. x^2-2xy+10x-10y+25 =x²+10x+25 - 2xy-10y=(x+5)²-2y(x+5)=(x+...