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If the square of X - 4xy + the square of 5Y + 6y + 9 = 0, find (2 / X to the power of 2011 * 1 / y to the power of 2013 equals 0
The solution is as follows: square of X - 4xy + square of 5Y + 6y + 9 = 0, that is, square of X - 4xy + square of 4Y + square of Y + 6y + 9 = 0, that is, (x-2y) & # 178; + (y + 3) & # 178; = 0, that is, x-2y = 0, y + 3 = 0, that is, x = - 6, y = - 3, that is, the power of 1 / 2 x in 2011 * y in 2013 = the power of 1 / 2 x in 2011 * y in 2011 * y in 2013
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