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Given x ^ 2-xy = 10, xy-y ^ 2 = 20, find: x^2-y^2 x^-2xy+y^2
∵x^2-xy=10
∵xy-y^2=20
∴（x^2-xy）+（xy-y^2）=30
∴x^2-y^2=30
∵x^2-xy=10
∵xy-y^2=20
∴（x^2-xy）-（xy-y^2）=x^-2xy+y^2=-10
∴x^-2xy+y^2=-10
Given that x-xy = 20, xy-y = - 12, then X-Y =?
All in all, x-xy + (xy-y) = 20 + (- 12)
x－y＝8
How to simplify (1 / Y-1 / x) times (XY) / (x ^ 2-2xy + y ^ 2)
(1/y-1/x)*（xy）/（x^2-2xy+y^2） =(X-y)/(x-y)^2 =1/(x-y)
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