How to find that the square of x minus x minus 2 equals 0,

How to find that the square of x minus x minus 2 equals 0,


xx-x-2=0
(x-2)(x+1)=0
x-2=0,x+1=0
x1=2,x2=-1



How to calculate the square of X - 8x + 2 = 0
How to calculate? Forget to be happy for a while,
Want to know the formula to solve the problem!


ax^2+bx+c=0
△=b^2-4ac
x=(-b+√△)/2a
Or = (- B - √ △) / 2A
△=64-8=56
x=( 8±√56)/2=4±√14



If 8x2-16 = 0, then the value of X is___ .


If the coefficient is changed to 1, X2 = 2, and the square root, x = ± 2