(2x + 3) square = x square - 8x + 16

(2x + 3) square = x square - 8x + 16


(2x + 3) square = x square - 8x + 16
(2x+3)²=(x-4)²
(2x+3)²-(x-4)²=0
(2x+3+x-4)(2x+3-x+4)=0
(3x-1)(x+7)=0
x1=1/3 x2=-7



Lim x → 1 x squared-4x + 3 / X squared-9
But the standard answer is one in three


X = 1 and substituting it is



(x + 1 minus 1-1 / x) divided by (x minus the square of X-1 / x)


(x+1-1/(1-X))/(X-X^2/(X-1))
=(-X^2/(1-X))/(-X/(X-1))
=X