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If the absolute value of the difference between the two roots of the linear equation x ^ + MX + M-1 = 0 is 2, then the value of M is?
x1+x2=-m
x1*x2=m-1
Because the absolute value of x1-x2 = 2
So (x1 + x2) ^ 2-4 (x1 * x2) = (x1-x2) ^ 2
So m ^ 2-4m + 4 = 4
M = 0 or M = 4
It is known that the equation MX | m-2 | + 2 (M + 1) x-3 = 0 is a quadratic equation with one variable, then M=______ ．
∵ the equation MX | m-2 | + 2 (M + 1) x-3 = 0 about X is a quadratic equation with one variable, ∵ m-2 | = 2, and m ≠ 0, the solution is m = 4, so fill in: 4
If the square of X + xy = 2 and the square of XY + y = - 1, then the square of x plus the square of Y=
The square formula: (x + y) is: (x + y) the following formula: (x + y) \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\; = 1 x + y = ± 1
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