If x ^ 2 + 2x + 1 + y ^ 2-8y + 16 = 0, find y / X. urgent!
x^2+2x+1+y^2-8y+16=0
(x+1)^2+(y-4)^2=0
x=-1,y=4
y/x=-4
Given X & # 178; + 2x & # 178; + 2Y + Y & # 178; + 2 = 0, find the power of x2006 + Y2007
x^2+2x+1+y^2+2y+1=0
(x+1)^2+(y+1)^2=0
Because (x + 1) ^ 2 ≠ 0 (y + 1) ^ 2 ≠ 0
So (x + 1) = 0 (y + 1) = 0
x=-1 y=-1
(-1)^2006+(-1)^2007=1-1=0
(x-4) ² = 10 for x?
X = 4 + radical ten or 4-radical ten
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