1、 Square of (- 2aX) * (- 2 / 5x to the fourth power, y to the cube, Z to the cube) / (- 1 / 2a to the fifth power, XY to the square) - 1 power 2、 The square of X - (x + 2) (X-2) - (x-1 / x) 3、 [(x + y) square - (X-Y) square] / (2XY)

1、 Square of (- 2aX) * (- 2 / 5x to the fourth power, y to the cube, Z to the cube) / (- 1 / 2a to the fifth power, XY to the square) - 1 power 2、 The square of X - (x + 2) (X-2) - (x-1 / x) 3、 [(x + y) square - (X-Y) square] / (2XY)

I can't understand the first question. You're not very clear. The second question = 2 + X + 1 / x) * (2-x + 1 / x) the third question = 2

Why can - [5 (X-Y)] ^ 3 become - [(2x-3y) + (3x-2y)] ^ 3 after decomposition

It's so simple
Both before and after decomposition are in the form of - (a) ^ 3, so we only need to consider how to decompose in brackets
5(x-y)=5x-5y
This five can be divided into two and three, right
therefore
5x-5y=2x+3x-2y-3y=(2x-3y)+(3x-2y)
It's the same as the one in brackets

Find several factorizations
1、 x²-y²+x³-y³
2、 (a+1)(a+3)(a+5)(a+7)+15
3、 a(a-b+2)-6b(b+1)